Draw the sterioisomers of 2-methylcyclohexanol.

Stereoisomers are the isomers in which atoms connectivity are same, but atom arranges itself in different positions in space (out of the plane, on the plane and inside the plain.

Maximum possible numbers of stereoisomers can be calculated by putting the value of n in 2ⁿ. Where n is the number of chiral carbons (carbon with all different atoms). In question, there are two chiral center (represented by y^*) , thus possible stereoisomers are 4 (2²=4).

Thus, possible structures are

Where 1 and 3 and 2 and 4 are mirror images of each other and these images are non superimposed , thus all the four are enantiomers or sterioisomers. There is no meso compound because there is chiral carbon but there is no internal plane of symmetry (chiral compound).

Thus, four stereoisomers are possible of 2-methyl cyclohexanol compound, where 1 and 2, 3 and 4 are enantiomers of each other and we get four stereoisomers.