Chapter 14: Q24P (page 640)
Explain the relative chemical shifts of the benzene ring protons in Figure 14.18.
Short Answer
For proton a it is 7.52 ppm.
For proton b it is 7.64 ppm.
For proton c it is 8.21 ppm.
Chapter 14: Q24P (page 640)
Explain the relative chemical shifts of the benzene ring protons in Figure 14.18.
For proton a it is 7.52 ppm.
For proton b it is 7.64 ppm.
For proton c it is 8.21 ppm.
All the tools & learning materials you need for study success - in one app.
Get started for freeWould it be better to use 1H NMR or 13C NMR spectroscopy to distinguish 1-butene, cis-2-butene, and 2-methylpropene? Explain your answer.
Where would you expect to find the NMR signal of relative to the TMS signal? (Hint: Magnesium is less electronegative than silicon.)
The followingNMR spectra are for four compounds, each with a molecular formula of . Identify the compounds.
a.
b.
c.
d.
Without referring to Table 14.1, label the proton or set of protons in each compound that gives the signal at the lowest frequency a, at the next lowest b, and so on.
Which underlined proton (or sets of protons) has the greater chemical shift (that is, the higher frequency signal)?
What do you think about this solution?
We value your feedback to improve our textbook solutions.