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Chapter 14: Q48P (page 669)

Draw a splitting diagram for the $H_{b}$ proton and give its multiplicity if
a. $J_{ba} = J_{bc}$ b. $J_{ba} = 2 J_{bc}$

Short Answer

Expert verified

a.

This has five peaks, called quintet.

b.

This has eight peaks i.e., double of quartet.

Step by step solution

01

Step-by-Step SolutionStep 1: Splitting diagram for Hbproton

a.

This shows five peaks i.e., a quintet.

b.

This shows eight peaks i.e., double of quartet.

02

Multiplicity

a. Here, $H_{b}$ proton is split into four peaks initially by the $H_{a}$ protons and further to five peaks, i.e. a quintet.

b. Here, $H_{b}$ proton is split into doublet of quartet, i.e. eight peaks by the $H_{c}$ protons.

So $J_{ba} = J_{bc}$ and $J_{ba} = 2 J_{bc}$ .

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Most popular questions from this chapter

Where would you expect to find the ${}^{1}H$ NMR signal of ${({CH}_{3})}_{2} Mg$ relative to the TMS signal? (Hint: Magnesium is less electronegative than silicon.)

Compound A, with molecular formula C₄H₉Cl, shows two signals in its ¹³C NMR spectrum. Compound B, an isomer of compound A, shows foursignals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and B.

How an ${}^{1}H$ NMR distinguish between the compounds in each of the following pairs?

a.

b.

c.

d.

e.

f.

g.

h.

i.

j.

When compound A ( $C_{5} H_{11} B r$ ) is treated with HBr, it forms compound B ( $C_{5} H_{11} B r$ ). The 1 H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1 H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.

How many hertz from the TMS signal is the signal occurring at 2.0 ppm

a. in a 300 MHz spectrometer?

b. in a 500 MHz spectrometer?

See all solutions

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