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Chapter 14: Q76P (page 680)

Identify the compound with a molecular formula C6H10O that gives the following DEPT 13C NMR spectrum:

Short Answer

Expert verified

The compound can be:

Step by step solution

01

DEPT spectrum

It is defined as Distortionless Enhancement by Polarization Transfer in which transfer of polarisation occurs from an excited nucleus to another. It is a type of double resonance program. In this, we can read the multiplicity directly by reducing CH coupling.

02

Identify compound from molecular formula

As per the given molecular formula we can find the number of carbon is 6 and hydrogen is 10 and the oxygen is present and the signal at 220 ppm shows the presence of the ketone having one methyl group and one CH group and three methylene groups.

03

Identify compound by DEPT spectra

As depicted by the DEPT the high-frequency signal is due to the methylene group and CH group showing these groups attached to carbonyl so the compound must be:

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Most popular questions from this chapter

Question:Identify each of the following compounds from its mass spectrum, IR spectrum, 1H and NMR spectrum:

a.

b.

[18]-Annulene shows two signals in its 1 H NMR spectrum: one at 9.25 ppm and the other to the right of the TMS signal at -2.88 ppm. What hydrogens are responsible for each of the signals?

Compound A, with molecular formula C4H9Cl, shows two signals in its 13C NMR spectrum. Compound B, an isomer of compound A, shows foursignals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and B.

Identify the compound with molecular formula C6H14 that is responsible for the following 1H NMR spectrum:

How would integration distinguish the 1 H NMR spectra of the following compounds?
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