Propose a mechanism for each of the following reactions:

Short Answer

Expert verified

a)

b)

Step by step solution

01

How will reaction proceed

a)In this reaction first lone pair of oxygen attacks on hydrogen then oxygen get positive charge and after that water will remove and positive charge is taken by that carbon where oxygen was attached. To form a stable carbocation methyl shift was there then carbon hydrogen will make double bond and ring occupied methyl groups on adjacent carbons.

b) Because of primary carbocation cannot be formed the dehydration is an E2 reaction. The alkene that results is protonated , and the proton that is removed is the one that results in formation of the most stable alkene.

02

 Step 2: Final answer

a)

In this reaction first lone pair of oxygen attacks on hydrogen then oxygen get positive charge and after that water will remove and positive charge is taken by that carbon where oxygen was attached. To form a stable carbocation methyl shift was there then carbon hydrogen will make double bond and ring occupied methyl groups on adjacent carbons.

b)

Because of primary carbocation cannot be formed the dehydration is an E2 reaction. The alkene that results is protonated , and the proton that is removed is the one that results in formation of the most stable alkene.

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