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Chapter 10: Q21P (page 472)

What alcohol would you treat with phosphorus oxychloride and pyridine to form each of the following alkenes?

Short Answer

Expert verified

1. It is a two step reaction.

2.In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation

5. As the carboanion intermediate is formed so the stability order 1° carboanion>2° carboanion>3° carboanion

Step by step solution

01

How SN1 reaction proceed

1. It is a two step reaction.

2.In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation

5. As the carboanion intermediate is formed so the stability order 1° carboanion>2° carboanion>3° carboanion

02

Final answer

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Most popular questions from this chapter

What stereoisomers are formed in the following reactions? Which stereoisomer is the major product?

a. the acid-catalyzed dehydration of 1-pentanol to 2-pentene

b. the acid-catalyzed dehydration of 3,4-dimethyl-3-hexanol to 3,4-dimethyl-3-hexene

Explain how 1-butanol can be converted into the following compounds:

Draw the product of each of the following reactions:

Propose a mechanism for each of the following reactions:

What stereoisomers do the following reactions form?
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