A compound reacts with methylmagnesium bromide followed by acidification to form the product with the following${}^{\mathbf{1}}\mathbf{H}$NMR spectrum. Identify the compound.

${}^1\mathrm{H}$NMR spectroscopy is another form ofabsorption spectroscopy known asProton NMR spectroscopy.

Under the appropriate condition in a magnetic field, a chemical compound absorbs radiofrequency in NMR spectroscopy, and a plot of absorption peaks versus intensity constitutes the NMR spectrum.

The given ${}^1\mathrm{H}$NMR spectrum is given by the compound2-phenyl-2-butanolin which the peak from 7.00 to 7.43 ppm is of phenyl hydrogen, the peak at 1.9 ppm is of the proton attached directly to oxygen, the peak at 1.8 ppm is of hydrogen attached to the secondary carbon and the peak at 1.7 ppm is of hydrogen attached to a primary carbon.

The structure of 2-phenyl-2-butanol is shown as:

2-phenyl-2-butanol

The formation of 2-phenyl-2-butanol by reacting it with the Grignard reagent, methyl magnesium bromide followed by acidificationwill be the carbonyl compound with three carbon long having phenyl substituent attach directly to the carbonyl carbon that is 1-phenyl-1-propanone.

The formation of 2-phenylbutan-2-ol is shown as follows:

Formation of 2-phenylbutan-2-ol