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Chapter 18: Q62P (page 916)

Which of the following compounds reacts with HBr more rapidly?

Short Answer

Expert verified

Following Compound reacts with HBr more rapidly:

Step by step solution

01

Effects of substitutions on reactivity of benzene ring

Strongly activating substituents make the benzene ring reactive towards electrophilic substitution via electron donation by resonance.Mostly activating substituents are -NH2, -NHR, -NR2, -OH, -OR.

02

Reactivity of HBr towards second structure

The given compound is having one methoxy group (Strongly activating substituent) in para position. Electron donating group present in a benzene ring increases the reactivity because it forms stable carbocation intermediate by resonance electron donation.

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Most popular questions from this chapter

Propose a mechanism for the following reaction that explains why the configuration of the asymmetric center in the reactant is retained in the product:

Show two pairs of reagents that would each result in formation of the following compound:

Question: Name the following:

a.

b.

c.

d.

What is the major product of a Friedel-crafts alkylation using the following alkyl chlorides?

a. CH3CH2Cl

b. CH3CH3CH2Cl

c. CH3CH2CH(Cl)CH3

d. (CH3)3CCl

e. (CH2)2CHCH2Cl

f. CH2CHCH2Cl

Explain why fluorobenzene is more reactive than chlorobenzene toward electrophilic aromatic substitution but chloromethyl benzene is more reactive than fluoromethylbenzene.
See all solutions

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