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Chapter 1: Q-1-49P (page 2)

Draw a Lewis structure for each of the following:

  1. N2H4
  2. CO32-
  3. N2H2
  4. CO2
  5. HOCl

Short Answer

Expert verified

a. N2H2

=10+4=14

b. CO32-

=4+18+2=24

c. N2H2

=10+2=12

d. C02

=4+12=16

e. HOCl

=1+6+7+14

Step by step solution

01

Determine the total number of valence electrons.

a. N2H2

=10+4=14

b. CO32-

=4+18+2=24

c. N2H2

=10+2=12

d. C02

=4+12=16

e. HOCl

=1+6+7+14

02

Distribute the atoms, form bonds and fill in their octets

Use the number of valence electrons determined in step1 to fill up the octet.

a. N2H4


Bonded electrons =10

Lone pair of electrons=2


b. CO32-

Bonded electrons=8

Lone pair of electrons =8

c. N2H2

Bonded electrons=8

Lone pair of electrons=2

d. CO2

Bonded electrons =8

Lone pair of electrons =4

e. HOCl

Bonded electrons =4

Lone pair of electrons= 5

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