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Chapter 1: Q27P (page 28)

What orbitals are used to form 10 sigma bonds in propane( CH 3CH 2CH3)?

Short Answer

Expert verified

In propane 2, sigma bonds are formed by SP3 -SP3overlap and rest eight sigma bonds are formed by the overlap of SP3with s-orbital.

Step by step solution

01

Identifying the type of sigma bonds in propane

InthereCH3CH2CH3 are 10 sigma bonds which consist of 2 C-Cbonds and rest 8 C-Hbonds.

02

Identifying the orbitals used 

All the bonds in propaneCH 3CH 2CH3are single bonds. To bond with four atoms, each carbon in propane will use 4SP3 orbitals. Among 4 SP3 orbitals, one is used to bond with the SP3 orbital of the next carbon, thus, forming C-Cbond.

The other 3SP3 orbitals are used to bond with s-orbitals of the hydrogen attached to the carbon, thus, forming C-Hbond.

03

Final conclusion

The 2C-C bonds are formed bySP3--SP3 overlap and the rest 8 C-Hsigma bonds are formed by SP3-Soverlap.

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Most popular questions from this chapter

The following compound has only one asymmetric centre. Why then does it have four stereoisomers?

The mass spectrum for a compound with molecular weight of 102 is shown below. Its IR spectrum has a broad, strong absorption at 3600 cm–1 and a

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a.Identify the compound.

b.Show the mechanism for formation of the peak at m/z= 84.

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b. Which of the following has a bond closest to the ionic end of the bond spectrum?

CH3NH2 CH3CH3 CH3F CH3OH

Explain why protonating aniline dramatically affects the compound’s UV spectrum, whereas protonating pyridine has only a small effect on that compound’s UV spectrum.

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