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Chapter 9: Q25P (page 419)

Which alkyl halide in each pair is more reactive in an E2 reaction with hydroxide ions?

Short Answer

Expert verified

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation

Step by step solution

01

How SN1 reaction proceed

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation

02

Final answer

a) In this more stable alkene will form.

b) In this more stable alkene will form as the double bonds are conjugated.

c) It has four hydrogen that can be removed to form an alkane with the two substituents on the Sp2carbon so it has a greater possibility of having an effective collision with the nucleophile than the other alkyl halide that has only two such hydrogens.

d) In this more stable alkene will form as the double bonds are conjugated.

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