What percentage of the reaction described in Problem 31 takes place by the E2 pathway when [HO-] = 0.0025 M?

Short Answer

Expert verified

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation.

Step by step solution

01

How SN1 reaction proceed

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation.

02

How SN2 reaction proceed

1. It is one step reaction.

2. In this nucleophile attacks the back side of the carbon.

3. In this one intermediate stage is formed.

4. In intermediate stage one group is leaving group and one group is attacking group.

5. In this inversion of reaction takes place.

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