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Chapter 9: Q82P (page 452)

Fill in the squares in the following chemical equations:

Short Answer

Expert verified

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation

Step by step solution

01

How SN1 reaction proceed

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3° carbocation>2° carbocation>1° carbocation

02

Final answer

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Most popular questions from this chapter

Draw the products of each of the following SN2/E2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed.

a.(3S,4S)-3-bromo-4-methylhexane + CH3O-

b.(3R,4R)-3-bromo-4-methylhexane + CH3O-

c.(3S,4R)-3-bromo-4-methylhexane + CH3O-

d.(3R,4S)-3-bromo-4-methylhexane + CH3O-

Which alkyl halide in each pair is more reactive in an E2 reaction with hydroxide ions?

Draw the products obtained from the solvolysis of each of the following compounds in ethanol:

When the following compound undergoes solvolysis in ethanol, three products are obtained. Propose a mechanism to account for the formation of these products.

A chemist wanted to synthesize the aesthetic 2-ethoxy-2-methylpropane. He used ethoxide ion and 2-chloro-2-methylpropane for his synthesis and ended up with no ether. What was the product of his synthesis? What reagents should he have used?
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