Which of the following pairs of dinucleotides are present in equal amounts in DNA?

A. CC and GG

B. CG and GT

C. CA and TG

D. CG and AT

E. GT and CA

F. TA and AT

Short Answer

Expert verified

The dinucleotides from pair ‘A’ CC and GG and pair ‘C’ CA and TG are present in equal amounts in DNA.

Step by step solution

01

Step-by-Step SolutionStep 1: Dinucleotides

A nucleotide is classified as mononucleotide, dinucleotide, trinucleotide, etc.A dinucleotide is a compound comprised of two nucleotides. There are a total of 16 pairs of nucleotides possible.A nucleotide is composed of nucleobase, pentose sugar, and phosphoric acid.

02

Dinucleotide pairs

There are a total of 16 pairs of nucleotides possible. The 16 pairs are as follows;

AT, AA, AC, AG, TT, TA, TC, TG, GT, GA, GC, GG, CT, CA, CC, CG.

The dinucleotides from pair ‘A’ CC and GG and pair ‘C’ CA and TG are present in equal amounts in DNA.

CA and TG form in equal amount since A pairs with T and C pairs with G as we know that dinucleotide are written in the5'3' directions.

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Most popular questions from this chapter

If one of the strands of DNA has the following sequence of bases running in the 5'-G-G-A-C-A-A-T-C-T-G-C-3'

a. what is the sequence of bases in the complementary strand?

b. what base is closest to the 5′-end in the complementary strand?

a. Using the single-letter abbreviations for the amino acids in Table 21.2, write the sequence of amino acids in a tetrapeptide represented by the first four different letters in your first name. Do not use any letter twice. (Because not all letters are assigned to amino acids, you might have to use one or two letters in your last name.)

b. Write one of the sequences of bases in mRNA that would result in the synthesis of that tetrapeptide.

c. Write the sequence of bases in the sense strand of DNA that would result in the formation of that fragment of mRNA.

The amino acid sequences of peptide fragments obtained from a normal protein were compared with those obtained from the same protein synthesized by a defective gene. They were found to differ in only one peptide fragment. Their amino acid sequences are shown here:

Normal: Gln-Tyr-Gly-Thr-Arg-Tyr-Val

Mutant: Gln-Ser-Glu-Pro-Gly-Thr

a. What is the defect in DNA?

b. It was later determined that the normal peptide fragment is an octapeptide with a C-terminal Val-Leu. What is the C-terminal amino acid of the mutant peptide?

Draw the structure for each of the following:

a. dCDP

b. dTTP

c. dUMP

d. UDP

e. guanosine triphosphate

f. adenosine 5’-monophosphate

Why is the codon a triplet rather than a doublet or a quartet?

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