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Chapter 23: Q31P (page 1097)

Question:Draw the products of the following reaction, where T is tritium:

Short Answer

Expert verified


When coenzyme B-12 acts upon the reactant, it gets added with the tritium attached to C3 and there forms a radical. Now, the C - OH bond breaks and it gets bonded with C3. Now the radical is formed at C2. At the same time, the oxidation state of cobalt in B-12 changed to +2. Now the radical at C2 is substituted with hydrogen in the coenzyme. Then the radical in the carbon in coenzyme is lost and the oxidation number of cobalt is regained. When the molecule is dehydrated, these products are obtained.

Step by step solution

01

Mechanism for the given reaction


When coenzyme B-12 acts upon the reactant, it gets added with the tritium attached to C3 and there forms a radical. Now, the C - OH bond breaks and it gets bonded with C3. Now the radical is formed at C2. At the same time, the oxidation state of cobalt in B-12 changed to +2. Now the radical at C2 is substituted with hydrogen in the coenzyme. Then the radical in the carbon in coenzyme is lost and the oxidation number of cobalt is regained. When the molecule is dehydrated, these products are obtained.

02

Step 2: Final product for the reaction

If the amount of coenzyme is limited, the product formed will be changed. The second hydrogen in the coenzyme B-12 will be substituted with tritium. Thus the final product is as shown below:

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Most popular questions from this chapter

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g. What coenzymes are used for carboxylation reactions?

h.What kinds of substrates do the carboxylating coenzymes work on?
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