Assign E or Z configuration to the following alkenes:

The cis–trans naming system works only for disubstituted alkenes having two substituents other than hydrogen on the double bond. But when trisubstituted and tetrasubstituted of the double bond are present then the E and Z system is used for describing alkene stereochemistry.

• Multiple-bonded atoms are equivalent to the same number of single-bonded atoms.
• Once the groups attached have been ranked look at the entire molecule. If the higher ranked groups on each carbon are on the same side of the double bond then alkene is said to have Z geometry and if present on opposite sides then the alkene has E geometry.

As ranking is atomic number dependent, more the atomic number higher will be ranking. So,

In ring:

• In the upper part, methyl is at second carbon from an alkene, havingthree carbon and one hydrogen attached.
• In the lower part of the ring, the second carbon from an alkene, hastwo carbon and two hydrogens attached.

So, the upper part of the ring is ranked 1.

In ${\text{-CO}}_2\text{H}$,${\text{-CH}}_2\text{OH}$ and ${\text{-CO}}_2\text{H}$:

• Incarbon${\text{-CH}}_2\text{OH}$ is attached to two hydrogens and one oxygen.
• Incarbon${\text{-CO}}_2\text{H}$ is attached to three oxygen.

So, ${\text{-CO}}_2\text{H}$rank 1

From the structure of the given compound, it can be seen both high ranking groups on the same side so the Z configuration.