Draw the more stable chair conformation of the following molecules, and estimate the amount of strain in each:

Chair conformation structure for six-membered ring is when atoms 2, 3, 5, and 6 lie in the same plane, atom 1 lies above the plane, and atom 4 lies below the plane.

Axial bonds are the bonds that are perpendicular or vertical to the ring plane. Equatorial bonds are approximately horizontal in the plane of the ring.

The energy difference between axial and equatorial conformations is due to steric strain caused by 1,3-diaxial interactions. The axial group on C1 is too close to the axial hydrogens three carbons away on C3 and C5, resulting in the steric strain.

Similarly, the axial group on C2 is too close to the axial hydrogens three carbons away on C4 and C6, resulting in the steric strain.

Conformation one possible

In this image, it can be seen that interactions are present and one gauche interaction is present.

One interaction of gives 3.8 kJ/mol energy and here two interactions are present giving 7.6 kJ/mol strain and one gauche interaction gives 3.8 kJ/mol. Hence, the total strain is 11.4 kJ/mol.

Conformation two possible

In this image, it can be seen thatinteractions are present.

One interaction of gives 4 kJ/mol energy and here two interactions are presently giving 8 kJ/mol strain and one gauche interaction gives 4 kJ/mol. Hence, the total strain is 12 kJ/mol.

Hence, it can be seen this structure has less strain and is hence more stable.

Conformation one is more stable

$2(\mathrm{H}\leftrightarrow {\mathrm{CH}}_2{\mathrm{CH}}_3)$