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Chapter 6: Q14E (page 181)

The following alkyl halide can be prepared by the addition of HBr to two different alkenes. Draw the structures of both (reddish-brown 5 Br).

Short Answer

Expert verified

The structure of alkenes is as follows;

H3C-CH2-CH=CH-CH3

H3C-CH2-CH2-CH=CH2

Step by step solution

01

Addition reaction

The reaction in which two or more molecules combine to form a single molecule is called an addition reaction.

02

Addition of HBr to alkene to form alkyl halide

The structure of the given alkyl halide is H3C-CH2-CH2-CH(Br)-CH3. Hence there are two possibilities by which the given alkyl halide is formed;

(a)H3C-CH2-CH=CH-CH3+HBr→H3C-CH2-CH2-CH(Br)-CH3(b)H3C-CH2-CH2-CH=CH2+HBr→H3C-CH2-CH2-CH(Br)-CH3

Using the above two alkene structures, we can get the alkyl halide resultant.

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Most popular questions from this chapter

Identify the following reactions as additions, eliminations, substitutions, or rearrangements:

a.

b.

c.

d.

Follow the flow of electrons indicated by the curved arrows in each of the following polar reactions, and predict the products that result:

Which of the following species are likely to be nucleophiles and which electrophiles? Which might be both?

Add curved arrows to the mechanism shown in Problem 6-25 to indicate the electron movement in each step.

For each alkene below, use curved arrows to show how it would react with a proton. Draw the carbocation that would form in each case.

a)

b)

c)
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