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Chapter 23: Q18P (page 773)

How would you prepare the following compound using a Michael reaction?

Short Answer

Expert verified

By the reaction between pent-1-ene-3-one and nitroethane we can prepare the given compound.

Step by step solution

01

Michael addition and donor group

First, we have to find out the Michael addition and donor group in the given compound since the carbonyl group is the accepter and then give number 1,2,3 to the carbon atoms of the compound after identification of the Michael addition and donor group break the bond between them and we get the reactant of this reaction.

02

The chemical reaction occurs:

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Most popular questions from this chapter

Treatment of a 1,3-diketone such as 2,4-pentanedione with base does not give an aldol condensation product. Explain.

Ethyl dimethyl acetoacetate reacts instantly at room temperature when treated with ethoxide ion to yield two products, ethyl acetate, and ethyl 2-methyl propanoate. Propose a mechanism for this cleavage reaction.

The following molecule was formed by an intramolecular aldol reaction. What dicarbonyl precursor was used for its preparation?

The following molecule was formed by a Robinson annulation reaction. What reactants were used?

What product would you expect to obtain from the base treatment of 1,6-cyclo-decanedione?
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