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Chapter 14: Q4P (page 427)

Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of HBr with the following compound:

Short Answer

Expert verified

Halogen halide reacts with alkene hydrogen attached to one sp2carbon of alkene and halide added to anothersp2alkene carbon; even when the double bond is in the ring compound, the result is the same.

Hydrogen halides, e.g., HCl, HBr, or HI, react with an alkene, e.g., ethylene form alkyl halide as the product

Step by step solution

01

Addition of hydrogen halide to an alkene

Halogen halide reacts with alkene hydrogen attached to one sp2carbon of alkene and halide added to anothersp2alkene carbon; even when the double bond is in the ring compound, the result is the same.

Hydrogen halides, e.g., HCl, HBr, or HI, react with an alkene, e.g., ethylene form alkyl halide as the product

02

Formation of 1,2 and 1,4 adducts

2,3-dimethylcyclohexa-1,3-diene having a double bond, reacts with hydrogen halide HBr to give the carbocation, which is resonance stabilized (two resonating structures).

Two carbocation forms get attacked by the nucleophile bromine ion to result in the formation of two different types of products (adducts):

  • 1,2 product is 6-bromo-1,6-dimethylcyclohex-1-ene
  • 1,4 product is 3-bromo-1,2-dimethylcyclohex-1-ene

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