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Chapter 3: Q16 P-c. (page 85)

Sight along the C2-C1 bond of 2-methylpropane (isobutane).

(c) Make a graph of energy versus angle of rotation around the C2-C1 bond.

Short Answer

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(c)

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01

Graph of energy versus angle of rotation

The eclipsed conformation is less stable than the staggered conformation. This is because it comprises more potential energy due to the torsional strain.

02

Graph of energy versus angle of rotation around the C2-C1 bond

(c) A particular molecule’s stability is inversely related to its energy. Hence, the atom possessing less energy is more stable. The atom with high energy is least stable. The graph of energy versus the angle of rotation can be given as:

Graph of energy versus angle of rotation

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Most popular questions from this chapter

Draw structures that meet the following descriptions (there are many

Possibilities):

(b) Two isomers with the formula C4H8O2

In each of the following sets, which structures represent the same compoundand which represent different compounds?

(c)

Locate and identify the functional groups in the following molecules.

Identify the functional groups in the following substances, and convert

each drawing into a molecular formula (red 5 O, blue 5 N).

Increased substitution around a bond leads to increased strain. Take the four substituted butanes listed below, for example. For each compound, sight along the C2–C3 bond and draw Newman projections of the most stable and least stable conformations. Use the data in Table 3-5 to assign strain-energy values to each conformation. Which of the eight conformations is most strained? Which is least strained?

(a) 2-Methylbutane

(b) 2,2-Dimethylbutane

(c) 2,3-Dimethylbutane

(d) 2,2,3-Trimethylbutane
See all solutions

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