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Chapter 10: Q10-25E-c (page 308)

How would you prepare the following compounds, starting with cyclopentene and any other reagents needed? (c) 3-Bromocyclopentene.

Short Answer

Expert verified

3-Bromocyclopentene can be formed in the following way:

Step by step solution

01

Step-by-step solutionStep 1: Chlorination

It means substitution of one hydrogen from the reactant, so that halogen atom can be added there.

02

Alkyl halide

Alkyl halides are also known as haloalkanes or halogenoalkanes. They contains one or more halogen substituents i.e. –Br, -Cl,-I,-F.

03

Preparation of 3-bromo-cyclopentene

The desired product 3-bromocyclopentene can be prepared by brominating cyclopantene.

The reaction is as follows:

Preparation of 3-bromocyclopentene

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Most popular questions from this chapter

Question: (S)-3-Methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane as the major product. Is the product chiral? What conclusions can you draw about the radical intermediate?

What products would you expect from reaction of the following alkenes with NBS? If more than one product is formed, show the structures of all.

Draw structures corresponding to the following IUPAC names: (a) 2,3-Dichloro-4-methylhexane.

The major product of the reaction of methylenecyclohexane with N-bromosuccinimide is 1-(bromomethyl)cyclohexene. Explain.

How might you use a Suzuki–Miyaura reaction to prepare the biarylcompounds below? In each case, show the two potential reactionpartners.
See all solutions

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