Write the products of the following acid–base reactions:$\begin{array}{l}\left(a\right)C{H}_{3}OH+H_{2}S{O}_4\rightleftarrows ?\\ \left(b\right)C{H}_{3}OH+NaN{H}_2\rightleftarrows ?\\ \left(c\right)C{H}_{3}N{H_3}^{+}+C{l}^{-}+NaOH\rightleftarrows ?\end{array}$

An acid and base reaction is a chemical reaction that occurs between an acid and a base. It can be used to determine pH

Acid and bases are important to many chemical processes, maintaining a stable internal environment in the human body, producing salt and water with the help of a neutralization process in which acid and base react to form a salt and water.

Acids differ in their ability to donate H⁺. Stronger acids, such as HCl, react almost completely with water, whereas weaker acids, such as acetic acid (CH₃COOH), react only slightly.The exact strength of a given acid HA in water solution is described using the acidity constant ()for the acid-dissociation equilibrium.

Example:$\begin{array}{l}{\text{HA+H}}_2\text{O}\rightleftarrows {\text{A}}^{-}{\text{+H}}_{\text{3}}{\text{O}}^{-}\\ K_a\underset{}{}\text{=}\underset{}{}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{+}{\text{][A}}^{-}\text{]}}{\left[HA\right]}\end{array}$

Acid strengths are normally using values rather than values, where the is the negative common logarithm of $K_a$:

$\text{p}K\text{a=-log}{K}_a$

The stronger acid has a smaller $\text{p}{K}_a$ , and the weaker acid has a larger $\text{p}{K}_a$.

The reaction will take place to a significant extent in the direction from stronger acid to weaker

acid.

It is given that all the reactions are acid and base reactions. In general, an acid donates a proton to the base, and a base abstracts a proton from the acids. The reaction always proceeds from a strong acid, strong base to weak acid, weak base.

The products of the following acid-base reaction are given below:

(a) Sulfuric acid is strong acid than methanol . Therefore it donates a proton to methanol.

(b) Methanol is a stronger acid than sodamide . Therefore methanol donates its proton to sodamide.

(c) Methyl ammonium chloride is a stronger acid than Sodium hydroxide (NaOH). Therefore it can donate its proton to Sodium Hydroxide (NaOH).