Chapter 11: 46cE (page 350)

Which reaction in each of the following pairs would you expect to be faster?
(c) The $S_{N} 2$ displacement on 2-bromopropane by $C H_{3} C H_{2} O^{-}$ or by $C N^{-}$

Short Answer

Expert verified

$C N^{-}$ $i s s h o w f a s t r e a c t i o n t h a n$ $C H_{3} C H_{2} O^{-}$

Step by step solution

SN2 reaction

It is a nucleophilic substitution reaction in which an old bond is broken and a new bond is formed both processes occur simultaneously. Hence, it’s a single-step reaction.

The two reacting species are involved in the rate-determining steps.

Nucleophile

Nucleophiles are the negatively charged ions or the neutral species having the lone pair of electrons that are ready for bonding.

Species react faster with 2−bromopropane

If the species are a better leaving group then it reacts faster with the nucleophile

The cyanide ion is more reactive than the ethoxide ion due to which cyanide ion easily replaces the bromide ion from 2-bromoprpane.

$C N^{-}$ is a better leaving group than $C H_{3} C H_{2} O^{-}$

${CN}^{-}$ $is show fast reaction than$ ${CH}_{3} {CH}_{2} O^{-}$

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Which reaction in each of the following pairs would you expect to be faster?
(c) The $S_{N} 2$ displacement on 2-bromopropane by $C H_{3} C H_{2} O^{-}$ or by $C N^{-}$

Short Answer

Step by step solution

SN2 reaction

Nucleophile

Species react faster with 2−bromopropane

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Which reaction in each of the following pairs would you expect to be faster?(c) TheSN2displacement on 2-bromopropane by CH3CH2O-or byCN-

Short Answer

Step by step solution

SN2 reaction

Nucleophile

Species react faster with 2−bromopropane

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Making Measurements

Nuclear Chemistry

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Organic Chemistry

Study anywhere. Anytime. Across all devices.

Which reaction in each of the following pairs would you expect to be faster?
(c) The $S_{N} 2$ displacement on 2-bromopropane by $C H_{3} C H_{2} O^{-}$ or by $C N^{-}$