Chapter 12: Q11-P (page 383)
Where might the following compound have IR absorptions?
Short Answer
Absorption bands seen at 2210-2260 \(c{m^{ - 1}}\), 1690 \(c{m^{ - 1}}\) and 1640-1680 \(c{m^{ - 1}}\).
Chapter 12: Q11-P (page 383)
Where might the following compound have IR absorptions?
Absorption bands seen at 2210-2260 \(c{m^{ - 1}}\), 1690 \(c{m^{ - 1}}\) and 1640-1680 \(c{m^{ - 1}}\).
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Get started for freeQuestion: Propose structures for compounds that meet the following descriptions:
(a)with IR absorptions at 3300 and 2150
(b)with a strong IR absorption at 3400
(c) with a strong IR absorption at 1715
(d) with IR absorptions at 1600 and 1500
The following carboxylic acid can't be prepared from an alkyl halide by either the nitrile hydrolysis route or the Grignard carboxylation route.Explain.
Question: Halogenated compounds are particularly easy to identify by their mass
spectra because both chlorine and bromine occur naturally as mixtures
of two abundant isotopes. Recall that chlorine occurs as 35Cl (75.8%)
and 37C (24.2%); and bromine occurs as 79Br (50.7%) and 81Br (49.3%).
At what masses do the molecular ions occur for the following formulas?
What are the relative percentages of each molecular ion?
(a)Bromomethane, CH3Br
(b)1-Chlorohexane, C6H13Cl
Nicotine is a diamino compound isolated from dried tobaccoleaves. Nicotinehas two rings and=162.1157 by high-resolution mass spectrometry. Give a molecular formula for nicotine, and calculate the number of double bonds.
Assume that you are carrying out the base-induced dehydrobromination of 3-Bromo-3-methyl pentane (Section 11-7) to yield an alkene. How could you use IR spectroscopy to tell which of three possible elimination products is formed, if one includes E/Z isomers?
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