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Chapter 1: Problem 20

Select the correct alternative from the given choices. How many molecules would be there in \(0.01\) moles of sodium hydroxide? (a) \(6.023 \times 10^{23}\) (b) \(6.023 \times 10^{21}\) (c) \(6.023 \times 10^{22}\) (d) \(6.023 \times 10^{20}\)

Short Answer

Expert verified
Options: (a) \(6.023 \times 10^{23}\) (b) \(6.023 \times 10^{21}\) (c) \(6.023 \times 10^{22}\) (d) \(6.023 \times 10^{20}\) Answer: (b) \(6.023 \times 10^{21}\)

Step by step solution

01

Identify the given information

The given information is that there are 0.01 moles of sodium hydroxide (NaOH). We need to find out how many molecules are in this amount of NaOH.
02

Use Avogadro's number

In order to find the number of molecules in a given amount of substance, we can use Avogadro's number (\(6.022 \times 10^{23}\) entities per mole).
03

Multiply the moles by Avogadro's number

To find the total number of molecules in 0.01 moles of NaOH, multiply the number of moles by Avogadro's number: Number of molecules = (0.01 moles) x (\(6.022 \times 10^{23}\) molecules/mole)
04

Calculate the result

Using a calculator, we find the total number of molecules: Number of molecules = (0.01) x (\(6.022 \times 10^{23}\)) Number of molecules = \(6.022 \times 10^{21}\)
05

Match the answer with the given options

Now, we look at the given options and find the answer that matches our result: (a) \(6.023 \times 10^{23}\) (b) \(6.023 \times 10^{21}\) (c) \(6.023 \times 10^{22}\) (d) \(6.023 \times 10^{20}\) The closest match to our calculated answer is (b) \(6.023 \times 10^{21}\). Therefore, there are \(6.023 \times 10^{21}\) molecules in 0.01 moles of sodium hydroxide.

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