Calculate the molarity of a solution obtained by mixing \(250 \mathrm{ml}\) of \(0.5 \mathrm{M}\) HCl with \(750 \mathrm{ml}\) of \(2 \mathrm{M}\) HCl. (a) \(1.8\) (b) \(2.0\) (c) \(1.6\) (d) \(0.8\)

Short Answer

Expert verified
(a) 0.5 (b) 1.0 (c) 1.6 (d) 2.0 Answer: (c) 1.6

Step by step solution

01

Write down the given information

We know the initial molarities and volumes of the two HCl solutions: \(M_1\) = \(0.5\mathrm{M}\) \(V_1\) = \(250\mathrm{ml}\) \(M_2\) = \(2\mathrm{M}\) \(V_2\) = \(750\mathrm{ml}\)
02

Calculate the final volume

Sum the initial volumes to find the final volume: \(V_f = V_1 + V_2 = 250\mathrm{ml} + 750\mathrm{ml}\) \(V_f = 1000\mathrm{ml}\)
03

Use the formula to find the final molarity

Plug the initial molarities and volumes, along with the final volume, into the formula: \(M_1V_1 + M_2V_2 = M_fV_f\) \((0.5\mathrm{M})(250\mathrm{ml}) + (2\mathrm{M})(750\mathrm{ml}) = M_f(1000\mathrm{ml})\)
04

Solve for the final molarity

Divide both sides of the equation by 1000 ml to solve for the final molarity: \(M_f = \frac{(0.5\mathrm{M})(250\mathrm{ml}) + (2\mathrm{M})(750\mathrm{ml})}{1000\mathrm{ml}}\) \(M_f = \frac{125\mathrm{mmol} + 1500\mathrm{mmol}}{1000\mathrm{ml}}\) \(M_f = \frac{1625\mathrm{mmol}}{1000\mathrm{ml}}\) \(M_f = 1.625\mathrm{M}\) Since the nearest answer provided is 1.6, the correct response is (c) 1.6.

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