Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 44

For each of the questions, four choices have been provided. Select the correct alternative. In the formation of \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) from \(\mathrm{NO}_{2}\) the rates of production of (a) \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) are equal (b) \(\mathrm{NO}\) is double the rate of consumption of \(\mathrm{NO}_{2}\) (c) \(\mathrm{NO}\) is twice the rate of production of \(\mathrm{O}_{2}\) (d) \(\mathrm{O}_{2}\) is twice the rate of production of \(\mathrm{NO}\)

Short Answer

Expert verified
Answer: (a) NO and O₂ are produced at equal rates.

Step by step solution

01

Write the balanced chemical equation

We first need to write the balanced chemical equation for the given reaction. 2 NO₂ → NO + O₂
02

Find the rate law expression for each species

Using the stoichiometry coefficients in the balanced chemical equation, we can find the rate law expressions for each species. Rate of consumption of NO₂ = -d[NO₂]/dt Rate of production of NO = d[NO]/dt Rate of production of O₂ = d[O₂]/dt
03

Relate rates using stoichiometry

As we can see from the balanced chemical equation, for every 2 moles of NO₂ consumed, 1 mole of NO and 1 mole of O₂ are produced. So, we have: 1/2 × (-d[NO₂]/dt) = d[NO]/dt 1/2 × (-d[NO₂]/dt) = d[O₂]/dt Comparing the rate expressions, we find that the rate of production of NO and O₂ are equal. So, the correct alternative is: (a) NO and O₂ are produced at equal rates

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For each of the questions, four choices have been provided. Select the correct alternative. For a reaction \(\mathrm{A}+\mathrm{B} \rightleftarrows \mathrm{C}+\mathrm{D}\), if the activation energy of backward reaction is more than that of forward reaction, the forward reaction is (a) endothermic (b) exothermic (c) reaction need not necessarily involve heat changes (d) cannot be predicted

For each of the questions, four choices have been provided. Select the correct alternative. Which among the following reactions is an example of instantaneous reaction under normal conditions? (a) \(2 \mathrm{H}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{N}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{NO}\) (c) \(\mathrm{NaOH}+\mathrm{HCl} \rightarrow \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\)

For each of the questions, four choices have been provided. Select the correct alternative. Which of the following \(\mathrm{K}_{\mathrm{c}}\) values corresponds to the maximum yield of the products? (a) \(9.2 \times 10^{2}\) (b) \(1.8 \times 10^{-15}\) (c) \(2.8 \times 10^{3}\) (d) \(3.4 \times 10^{-25}\)

For each of the questions, four choices have been provided. Select the correct alternative. According to Le Chatelier's principle, (a) an increase in pressure always causes a change in position of equilibrium for any reaction (b) the yield of \(\mathrm{NH}_{3}\) decreases from its constituents at lower temperature (c) an increase in temperature causes a decrease in the value of \(\mathrm{K}_{\mathrm{c}}\) for an exothermic reaction (d) the \(\mathrm{K}_{\mathrm{c}}\) is decreased for the reaction \(\mathrm{A}_{(\mathrm{s})}+\mathrm{B}_{(\mathrm{g})}\) \(\rightarrow \mathrm{C}_{(\mathrm{g})}\), if the concentration of \(\mathrm{A}\) is increased

The slope obtained by drawing a tangent at time " \(\mathrm{t}\) " on the curve for the concentration of reactants vs time is equal to instantaneous rate.
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

Chemical Reactions

Read Explanation

The Earths Atmosphere

Read Explanation

Organic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free