For each of the questions, four choices have been provided. Select the correct alternative. What is the maximum number of electrons, present in an orbit whose angular momentum is \(\frac{2 \mathrm{~h}}{\pi}\) ? (a) 18 (b) 2 (c) 32 (d) 8

Short Answer

Expert verified
Answer: The maximum number of electrons in the orbit is 8.

Step by step solution

01

Recall Bohr's Quantization Rule

According to Bohr's quantization rule for angular momentum, the angular momentum of an electron in an orbit \((L)\) is given by: \(L = mvr = \frac {nh}{2\pi}\) Where \(m\) is the mass of the electron, \(v\) is its velocity, \(r\) is the radius of the orbit, \(n\) is the principal quantum number, and \(h\) is the Planck's constant.
02

Find the principal quantum number (n)

In this exercise, we are given the angular momentum of the orbit as \(\frac{2h}{\pi}\). We will use Bohr's quantization rule to find the principal quantum number by equating the given angular momentum with the formula: \(\frac{2h}{\pi} = \frac {nh}{2\pi}\) Dividing both sides by \(h\) and multiplying by \(2\pi\), we obtain: \(2 = n\) So, the principal quantum number (\(n\)) for this orbit is 2.
03

Determine the maximum number of electrons

The maximum number of electrons in an orbit can be determined using the formula: \(max~electrons = 2n^2\) Substituting the value of \(n\) we found in step 2, we get: \(max~electrons = 2(2^2) = 2(4) = 8\) The maximum number of electrons in the orbit is 8, which corresponds with choice (d) in the exercise.

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Most popular questions from this chapter

For each of the questions, four choices have been provided. Select the correct alternative. Energy of an electron in a particular orbit of single electron species of beryllium is the same as the energy of an electron in the ground state of hydrogen atom. Identify the orbit of beryllium. (a) 1 (b) 2 (c) 3 (d) 4

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