For each of the questions, four choices have been provided. Select the correct alternative. Which of the following sets of quantum numbers is correct for an electron in \(3 \mathrm{~d}\) orbital? (a) \(3,0,0,+1 / 2\) (b) \(3,1,1,-1 / 2\) (c) \(3,2,1,+1 / 2\) (d) \(3,2,3,-1 / 2\)

Short Answer

Expert verified
Answer: The correct set of quantum numbers for an electron in a 3d orbital is (c) \(3,2,1,+1 / 2\).

Step by step solution

01

Principal Quantum Number (n)

For a 3d orbital, the principal quantum number (n) must be equal to 3.
02

Angular Momentum Quantum Number (l)

For d orbitals, the angular momentum quantum number (l) must be equal to 2.
03

Magnetic Quantum Number (m_l)

The magnetic quantum number (m_l) can have integer values ranging from -l to +l, inclusive. For d orbitals (l=2), m_l can be -2, -1, 0, 1, or 2.
04

Electron Spin Quantum Number (m_s)

The electron spin quantum number (m_s) can have two values: +1/2 and -1/2.
05

Compare and Select the Correct Set of Quantum Numbers

Compare each set of given quantum numbers to the values derived for a 3d orbital: (a) \(3,0,0,+1 / 2\) - l is incorrect (b) \(3,1,1,-1 / 2\) - l is incorrect (c) \(3,2,1,+1 / 2\) - n, l, m_l, and m_s are all within the correct range (d) \(3,2,3,-1 / 2\) - m_l is incorrect Only option (c) has the correct values for all four quantum numbers. Therefore, the correct set of quantum numbers for an electron in a 3d orbital is: (c) \(3,2,1,+1 / 2\)

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