Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Problem 25

An element with atomic number " 32 " belongs to (a) 4 th period, VIA group (b) 3 rd period, IVA group (c) 4 th period, IVA group (d) 5 th period, VA group

Short Answer

Expert verified
Question: Determine the period and group of an element with atomic number 32. Answer: The element with atomic number 32 belongs to the 4th period, IVA group.

Step by step solution

01

Understanding the periodic table structure

The periodic table is organized into periods (rows) and groups (columns). In order to solve this problem, we need to know the general structure of the periodic table and identify the row and column that the element with atomic number 32 belongs to.
02

Use atomic number to determine period

For Atomic Number (Z) from 1 to 32, the periods can be determined as follows: - Period 1: Z = 1 to 2 - Period 2: Z = 3 to 10 - Period 3: Z = 11 to 18 - Period 4: Z = 19 to 36 Since the given atomic number is 32, it belongs to the 4th period.
03

Use atomic number to determine group

As we move from left to right in each period, the group number increases. The progression of the group numbers in this row is like this: - Group IA: Z = 19 (K) - Group IIA: Z = 20 (Ca) - Group IIIA: Z = 21 (Sc) to 31 (Ga) - Group IVA: Z = 32 (Ge) to 33 (As) Since the given atomic number is 32, it belongs to Group IVA (4A).
04

Combine the period and group

Now, we have determined that the element with atomic number 32 is located in the 4th period and Group IVA (4A).
05

Choose the correct option

We can now match our findings with the given options: (a) 4th period, VIA group (b) 3rd period, IVA group (c) 4th period, IVA group (d) 5th period, VA group The correct choice appears to be option (c), which corresponds to our findings. Thus, the element with atomic number 32 belongs to the 4th period, IVA group.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fill in the blanks. In the long form of the periodic table, ___ group elements can release maximum amount of energy by the addition of electron into its valence shell.

If the consecutive ionization energies of an element A are \(496,4564,6918,9542 \mathrm{~kJ} / \mathrm{mole}\) respectively, the formula of the oxide formed by \(\mathrm{A}\) is (a) \(\mathrm{A}_{2} \mathrm{O}_{3}\) (b) \(\mathrm{AO}\) (c) \(\mathrm{AO}_{2}\) (d) \(\mathrm{A}_{2} \mathrm{O}\)

Fill in the blanks. In the periodic table, vertical columns of elements are called ___ and horizontal rows of elements are called ___.

5f series elements are known as (a) lanthanides (b) representative elements (c) transition elements (d) actinides

Which one of the following electronic configuration corresponds to the element with maximum electropositive character? (a) \([\mathrm{Kr}] 5 \mathrm{~s}^{1}\) (b) \([\mathrm{Ne}] 3 \mathrm{~s}^{1}\) (c) [Ar]4s (d) [Xe]6s
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free