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Chapter 4: Problem 37

Which of the following elements has maximum electronegativity? (a) \(\overline{\mathrm{P}}\) (b) \(\mathrm{S}\) (c) \(\mathrm{Al}\) (d) \(\mathrm{Si}\)

Short Answer

Expert verified
Answer: The element with the maximum electronegativity among the given elements is S (sulfur).

Step by step solution

01

Look up electronegativity values

First, we should look up the electronegativity values of the given elements (P, S, Al, and Si) on the Pauling scale. Here are the values we need: - Electronegativity of P: 2.19 - Electronegativity of S: 2.58 - Electronegativity of Al: 1.61 - Electronegativity of Si: 1.90
02

Compare electronegativity values

Now that we have the electronegativity values of each element, we can compare the values to determine which element has the maximum electronegativity. Here is a comparison: - P (2.19) vs S (2.58): S has a higher electronegativity. - S (2.58) vs Al (1.61): S has a higher electronegativity. - S (2.58) vs Si (1.90): S has a higher electronegativity. Since sulfur (S) has a higher electronegativity value than all the other elements in the list, it has the maximum electronegativity among the given elements.
03

Answer

The element with the maximum electronegativity among the given elements is S (sulfur).

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State whether the following statements are true or false. Among the isoelectronic ions \(\mathrm{Na}^{+}, \mathrm{Mg}^{2+}\) and \(\mathrm{Al}^{3+}\), \(\mathrm{Na}^{+}\) ion have the largest size.

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