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Chapter 6: Problem 20

According to Lewis theory, neutralization is the (a) transfer of proton from acid to base (b) transfer of proton from base to acid (c) transfer of electron pair from acid to base (d) transfer of electron pair from base to acid

Short Answer

Expert verified
Answer: (d) transfer of electron pair from base to acid

Step by step solution

01

Option 1: Transfer of proton from acid to base

According to the Bronsted-Lowry theory, neutralization occurs when a proton (H+) is transferred from an acid to a base. However, this option does not represent the Lewis theory's perspective on neutralization.
02

Option 2: Transfer of proton from base to acid

This option is also incorrect, as it refers to the reverse process of neutralization in the Bronsted-Lowry theory, where a proton is transferred from a base to an acid. Lewis theory's focus is on electron pairs, not proton transfer.
03

Option 3: Transfer of electron pair from acid to base

According to Lewis theory, an acid is an electron pair acceptor, and a base is an electron pair donor. In this option, the electron pair is being transferred from the acid to the base, which is inconsistent with the definition of acids and bases in Lewis theory. Thus, this option is incorrect.
04

Option 4: Transfer of electron pair from base to acid

This option is correct. In Lewis theory, neutralization occurs when an electron pair is transferred from a base, which is an electron pair donor, to an acid, which is an electron pair acceptor. This process results in the formation of a stable compound, neutralizing the acidic and basic properties of the original substances. So, the correct option is: (d) transfer of electron pair from base to acid

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Most popular questions from this chapter

Fill in the blanks. The salt obtained by partial neutralization of sodium hydroxide and sulphuric acid is____ in nature.

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The basicity of acetic acid is the same as the basicity of____. (a) \(\mathrm{HNO}_{3}\) (b) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (c) \(\mathrm{H}_{3} \mathrm{PO}_{4}\) (d) \(\mathrm{H}_{2} \mathrm{CO}_{3}\)

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