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Chapter 6: Problem 29

The spectator ions in the hydrolysis of \(\left(\mathrm{NH}_{4}\right)_{2}\) \(\mathrm{CO}_{3}\) are (a) \(\mathrm{NH}_{4}^{+}, \mathrm{H}^{+}, \mathrm{OH}^{-}\) (b) \(\mathrm{NH}^{+}{ }_{4}, \mathrm{CO}_{3}{ }^{2-}, \mathrm{H}^{+}, \mathrm{OH}^{-}\) (c) \(\mathrm{CO}_{3}^{2-}, \mathrm{H}^{+}, \mathrm{OH}^{-}\) (d) no spectator ions

Short Answer

Expert verified
(a) NH4^+ (b) CO3^2- (c) Both (a) and (b) (d) No spectator ions Answer: (d) No spectator ions

Step by step solution

01

1. Write the balanced equation for hydrolysis of (NH4)2CO3

First, we need to write down the balanced equation for the hydrolysis reaction that takes place when (NH4)2 CO3 dissolves in water: (NH4)2 CO3 (s) + 2 H2O (l) -> 2 NH4^+ (aq) + CO3^2- (aq) + 2 H2O (l) Here, (NH4)2 CO3 (s) dissociates into its ions, 2NH4^+ and CO3^2- in water.
02

2. Write the balanced equation for the reaction with water

Next, we need to write the general equation of the reaction of the weak acid-base pair between the ions and water. In this case, NH4^+ and CO3^2- will react with water. NH4^+ (aq) + H2O (l) <=> NH3 (aq) + H3O^+ (aq) CO3^2- (aq) + H2O (l) <=> HCO3^- (aq) + OH^- (aq)
03

3. Identify the spectator ions

Spectator ions are those which do not participate in the reaction and remain unchanged. From the balanced equation, NH4^+ (aq) and CO3^2- (aq) react with water, thus they are not spectator ions. H3O^+ (aq) and OH^- (aq) are not spectator ions either, as they are the products of the reactions. In this case, there are no spectator ions among the given options. Therefore, the answer is: (d) no spectator ions

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