Which among the following pairs of acid and base are weak respectively? (a) \(\mathrm{HCOOH}\) and \(\mathrm{NH}_{4} \mathrm{OH}\) (b) \(\mathrm{HCl}\) and \(\mathrm{NaOH}\) (c) \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{KOH}\) (d) \(\mathrm{HClO}_{4}\) and \(\mathrm{CsOH}\)

Short Answer

Expert verified
a. HCOOH and NH4OH b. HCl and NaOH c. CH3COOH and KOH d. HClO4 and CsOH Answer: (a) HCOOH and NH4OH

Step by step solution

01

Analyze Pair (a)

The given pair (a) is \(\mathrm{HCOOH}\) and \(\mathrm{NH}_{4} \mathrm{OH}\). \(\mathrm{HCOOH}\), or formic acid, is a weak acid because it does not ionize completely in water. \(\mathrm{NH}_{4} \mathrm{OH}\), or ammonium hydroxide, is a weak base as it partially donates \(\mathrm{OH}^-\) ions in water. So, pair (a) contains a weak acid and a weak base.
02

Analyze Pair (b)

The given pair (b) is \(\mathrm{HCl}\) and \(\mathrm{NaOH}\). \(\mathrm{HCl}\), or hydrochloric acid, is a strong acid as it ionizes completely in water. \(\mathrm{NaOH}\), or sodium hydroxide, is a strong base as it completely donates \(\mathrm{OH}^-\) ions in water. So, pair (b) contains a strong acid and a strong base.
03

Analyze Pair (c)

The given pair (c) is \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{KOH}\). \(\mathrm{CH}_{3} \mathrm{COOH}\), or acetic acid, is a weak acid because it does not ionize completely in water. \(\mathrm{KOH}\), or potassium hydroxide, is a strong base as it completely donates \(\mathrm{OH}^-\) ions in water. So, pair (c) contains a weak acid and a strong base.
04

Analyze Pair (d)

The given pair (d) is \(\mathrm{HClO}_{4}\) and \(\mathrm{CsOH}\). \(\mathrm{HClO}_{4}\), or perchloric acid, is a strong acid as it ionizes completely in water. \(\mathrm{CsOH}\), or cesium hydroxide, is a strong base as it completely donates \(\mathrm{OH}^-\) ions in water. So, pair (d) contains a strong acid and a strong base.
05

Identify the weak acid and weak base pair

After analyzing all the given pairs, we found that only pair (a) contains a weak acid and weak base (\(\mathrm{HCOOH}\) and \(\mathrm{NH}_{4} \mathrm{OH}\)). Therefore, the answer is (a) \(\mathrm{HCOOH}\) and \(\mathrm{NH}_{4} \mathrm{OH}\).

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