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Chapter 6: Problem 7

State whether the following statements are true or false. \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} 24 \mathrm{H}_{2} \mathrm{O}\) gives reactions of both \(\mathrm{K}^{+}\) and \(\mathrm{Al}^{+3}\) ions respectively.

Short Answer

Expert verified
Answer: True.

Step by step solution

01

Analyze the given compound

The given compound is \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} 24 \mathrm{H}_{2} \mathrm{O}\). This is a double salt containing potassium sulfate (\(\mathrm{K}_{2} \mathrm{SO}_{4}\)) and aluminum sulfate (\(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\)). Double salts dissociate into their constituent ions when dissolved in water.
02

Determine the ions produced when the compound is dissolved in water

When the given double salt is dissolved in water, it will dissociate into its constituent ions. Potassium sulfate will produce potassium ions \((\mathrm{K}^{+})\) and sulfate ions \((\mathrm{SO}_{4}^{2-})\): $$ \mathrm{K}_{2}\mathrm{SO}_{4} \rightarrow 2\mathrm{K}^{+} + \mathrm{SO}_{4}^{2-} $$ Similarly, aluminum sulfate will produce aluminum ions \((\mathrm{Al}^{+3})\) and sulfate ions \((\mathrm{SO}_{4}^{2-})\): $$ \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \rightarrow 2\mathrm{Al}^{+3} + 3\mathrm{SO}_{4}^{2-} $$
03

Conclusion

From our analysis, we can see that when the given double salt is dissolved in water, it does produce potassium ions \((\mathrm{K}^{+})\) from potassium sulfate and aluminum ions \((\mathrm{Al}^{+3})\) from aluminum sulfate. Therefore, the statement "the compound \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} 24 \mathrm{H}_{2} \mathrm{O}\) gives reactions of both \(\mathrm{K}^{+}\) and \(\mathrm{Al}^{+3}\) ions" is true.

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Most popular questions from this chapter

Which of the following is not a base according to any of the theories? (a) \(\mathrm{Mg}(\mathrm{OH})_{2}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) (d) \(\mathrm{BF}_{3}\)

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