Fill in the blanks. During electrolysis of molten \(\mathrm{PbBr}_{2}\), ___ fumes are liberated at the anode.

Short Answer

Expert verified
Answer: Bromine gas fumes.

Step by step solution

01

Understanding Electrolysis

Electrolysis is a process in which an electric current is used to drive a non-spontaneous redox reaction. In this case, we are given a molten \(\mathrm{PbBr}_{2}\) compound undergoing electrolysis. In electrolysis, oxidation events happen at the anode, while reduction events occur at the cathode.
02

Find the ions present in molten PbBr2

Molten \(\mathrm{PbBr}_{2}\) is a liquid, and consists of ions. The ions present will be the cations \(\mathrm{Pb}^{2+}\) and anions \(\mathrm{Br}^{-}\), since \(\mathrm{PbBr}_{2}\) dissociate into its constituent ions when in molten state.
03

Determine the reactions happening at the Anode

At the anode during electrolysis, the oxidation reaction will take place. The anode is negatively charged and as a result it will attract the negatively charged ions, that is, the bromide ions (\(\mathrm{Br^{-}}\)). Bromide ions will be oxidized into bromine gas. The oxidation half-reaction can be written as: \(\mathrm{2Br^{-}} \rightarrow \mathrm{Br}_{2} + 2 e^{-}\)
04

Determine the fumes liberated at the Anode

Now, we can see that the anode produces \(\mathrm{Br}_{2}\) gas in the oxidation half-reaction. So, the fumes liberated in the electrolysis of molten \(\mathrm{PbBr}_{2}\) at the anode are: Bromine gas fumes.

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