Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 7: Problem 18

The metal deposited first at the cathode when a solution containing \(\mathrm{Fe}^{+2}, \mathrm{Cu}^{+2}\) is electrolyzed is (a) \(\mathrm{Fe}\) (b) \(\mathrm{Cu}\) (c) \(\mathrm{Fe}^{+3}\) (d) both 1 and 2

Short Answer

Expert verified
Answer: (b) \(\mathrm{Cu}\)

Step by step solution

01

List the reduction reactions and their respective reduction potentials.

The reduction potentials of the \(\mathrm{Fe}^{+2}\) and \(\mathrm{Cu}^{+2}\) ions are as follows: \(\mathrm{Fe}^{2+} + 2e^{-} \rightarrow \mathrm{Fe}\), Reduction potential = -0.44 V \(\mathrm{Cu}^{2+} + 2e^{-} \rightarrow \mathrm{Cu}\), Reduction potential = +0.34 V
02

Compare the reduction potentials.

Now that we have the reduction potentials, we can compare them. A higher reduction potential indicates a greater tendency for reduction to occur. In our case, the reduction potential of the \(\mathrm{Cu}^{+2}\) ion (+0.34 V) is higher than that of the \(\mathrm{Fe}^{+2}\) ion (-0.44 V).
03

Identify which metal will be deposited first.

Since \(\mathrm{Cu}^{+2}\) has a higher reduction potential, this means that it has a greater tendency to be reduced, or more likely to gain electrons and turn into a metal. Therefore, \(\mathrm{Cu}\) will be deposited first at the cathode when the solution containing \(\mathrm{Fe}^{+2}\) and \(\mathrm{Cu}^{+2}\) ions is electrolyzed.
04

Choose the correct answer among the options.

The correct answer is: (b) \(\mathrm{Cu}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a Daniel cell, if \(A\left(E_{0}=-0.76 v\right)\) and \(B(=-2.36 v)\) half- cells are taken then (a) \(\mathrm{B}\) acts as an anode (b) \(\mathrm{A}\) acts as an anode (c) \(\mathrm{B}\) acts as a cathode (d) cannot be predicted

The amount of copper deposited by the passage of 1 mole of electrons during the electrolysis of aqueous \(\mathrm{CuSO}_{4}\) solution is (a) \(63.5 \mathrm{~g}\) (b) \(31.75 \mathrm{~g}\) (c) \(159.5 \mathrm{~g}\) (d) \(79.75 \mathrm{~g}\)

Equimolar solutions of zinc sulphate and ferric sulphate are subjected to electrolysis. What is the ratio of Faradays of electricity required for deposition of one mole each of zinc and iron? (a) \(1: 2\) (b) \(2: 3\) (c) \(1: 3\) (d) \(3: 2\)

The order of ease of oxidation of the ions \(\mathrm{F}^{-}, \mathrm{OH}^{-}\) \(\mathrm{Br}^{-}, \mathrm{SO}_{4}^{2-}\) is (a) \(\mathrm{SO}_{4}^{2-}>\mathrm{F}^{-}>\mathrm{Br}^{-}>\mathrm{OH}^{-}\) (b) \(\mathrm{SO}_{4}^{2-}<\mathrm{Br}^{-}<\mathrm{OH}^{-}<\mathrm{F}\) (c) \(\mathrm{SO}_{4}^{2-}>\mathrm{F}^{-}>\mathrm{Br}^{-}>\mathrm{OH}^{-}\) (d) \(\mathrm{OH}^{-}<\mathrm{Br}^{-}<\mathrm{F}^{-}<\mathrm{SO}_{4}^{2-}\)

Which of the following concentrations of the electrolyte corresponds to maximum conductivity? (a) \(1 \mathrm{M} \mathrm{HCl}\) (b) \(1 \mathrm{M} \mathrm{HNO}_{3}\) (c) \(1 \mathrm{M} \mathrm{HClO}_{4}\) (d) \(1 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\)
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Chemical Reactions

Read Explanation

Chemistry Branches

Read Explanation

Inorganic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Physical Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free