In a Daniel cell, if \(A\left(E_{0}=-0.76 v\right)\) and \(B(=-2.36 v)\) half- cells are taken then (a) \(\mathrm{B}\) acts as an anode (b) \(\mathrm{A}\) acts as an anode (c) \(\mathrm{B}\) acts as a cathode (d) cannot be predicted

Short Answer

Expert verified
Answer: (a) B acts as an anode.

Step by step solution

01

Identify the half-cell with the higher and lower reduction potential.

We are given: A: \(E_{0}=-0.76 V\) B: \(E_{0}=-2.36 V\) Comparing these values, \(E_{0}\) of A is higher than that of B: \(-0.76 V > -2.36 V\)
02

Determine the anode and cathode

As the higher reduction potential half-cell acts as the cathode, and the lower reduction potential half-cell acts as the anode, we can conclude that: A acts as the cathode (because it has a higher reduction potential). B acts as the anode (because it has a lower reduction potential).
03

Choose the appropriate answer option

Based on the conclusions in Step 2, we can now determine the correct answer option: (a) B acts as an anode, which matches our conclusion that B is the anode. Therefore, the correct answer is option (a).

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