Pairs of electrodes and their corresponding standard electrode potentials are given. Arrange the cells constructed by these electrodes in increasing order of emf values. (1) Electrode \(\rightarrow \mathrm{A}, \mathrm{E}^{\circ}=-2.92 \mathrm{~V}\) and Electrode \(\rightarrow\) \(\mathrm{B}, \mathrm{E}^{\circ}=-2.71 \mathrm{~V}\) (2) Electrode \(\rightarrow \mathrm{C}, \mathrm{E}^{\circ}=-0.760 \mathrm{~V}\) and Electrode \(\rightarrow\) \(\mathrm{D}, \mathrm{E}^{\circ}=-0.44 \mathrm{~V}\) (3) Electrode \(\rightarrow \mathrm{B}, \mathrm{E}^{\circ}=-2.71 \mathrm{~V}\) and Electrode \(\rightarrow\) \(\mathrm{D}, \mathrm{E}^{\circ}=-0.44 \mathrm{~V}\) (4) Electrode \(\rightarrow \mathrm{A}, \mathrm{E}^{\circ}=-2.92 \mathrm{~V}\) and Electrode \(\rightarrow\) \(\mathrm{C}, \mathrm{E}^{\circ}=-0.76 \mathrm{~V}\) (a) 2143 (b) 1243 (c) 2413 (d) 2431

Step by step solution

01

Compute the emf of each cell

To compute the emf of each cell, subtract the standard electrode potential of the anode from that of the cathode as given by the formula: emf = \(E^{\circ}_{cathode} - E^{\circ}_{anode}\). (1) Cell 1: \(\text{emf}_1 = E_{B}^\circ - E_{A}^\circ = (-2.71) - (-2.92) = 0.21 \mathrm{~V}\) (2) Cell 2: \(\text{emf}_2 = E_{D}^\circ - E_{C}^\circ = (-0.44) - (-0.760) = 0.32 \mathrm{~V}\) (3) Cell 3: \(\text{emf}_3 = E_{D}^\circ - E_{B}^\circ = (-0.44) - (-2.71) = 2.27 \mathrm{~V}\) (4) Cell 4: \(\text{emf}_4 = E_{C}^\circ - E_{A}^\circ = (-0.76) - (-2.92) = 2.16 \mathrm{~V}\)

02

Arrange the cells in increasing order of emf values

To arrange the cells in increasing order of emf values, sort the emf values computed in Step 1: \(\text{emf}_1 = 0.21 \mathrm{~V}\) \(\text{emf}_2 = 0.32 \mathrm{~V}\) \(\text{emf}_4 = 2.16 \mathrm{~V}\) \(\text{emf}_3 = 2.27 \mathrm{~V}\) So, keeping this in mind: 1. Cell 1 2. Cell 2 4. Cell 4 3. Cell 3 Thus, the correct option is (b) 1243.

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