\(V_{1} \mathrm{ml}\) of unknown gas (A) \(+V_{2} \mathrm{ml}\) of \(\mathrm{O}_{2}\) \(\rightarrow\left(V_{1}+V_{2}\right) \mathrm{ml}\) of \(\mathrm{CO}_{2} .\) Gas 'A' may be (a) \(\mathrm{CO}\) (b) \(\left(\mathrm{CO}+\mathrm{CO}_{2}\right)\) in equal proportion (c) \(\mathrm{C}_{12} \mathrm{O}_{9}\) (d) \(\mathrm{C}_{3} \mathrm{O}_{2}\)

Short Answer

Expert verified
Answer: The unknown gas A is CO (carbon monoxide).

Step by step solution

01

Write down the possible reactions with each gas option

We will analyze the given options for the unknown gas and write down the possible balanced chemical equations for each option. (a) If gas A is CO, the balanced equation is: \(\mathrm{2CO} + \mathrm{O}_{2} \rightarrow \mathrm{2CO}_{2}\) (b) If gas A is a mixture of equal parts CO and CO2, then the balanced equation for the CO part is: \(\mathrm{2CO} + \mathrm{O}_{2} \rightarrow \mathrm{ 2CO}_{2}\). However, CO2 does not react with O2, so there will be no additional reaction in this case. (c) If gas A is C12O9, the balanced equation is: \(\mathrm{4C}_{12} \mathrm{O}_{9} + \mathrm{15O}_{2} \rightarrow \mathrm{24CO}_{2}\) (d) If gas A is C3O2, the balanced equation is: \(\mathrm{2C}_{3} \mathrm{O}_{2} + \mathrm{3O}_{2} \rightarrow \mathrm{6CO}_{2}\)
02

Determine the relationship between initial and final volumes for each option

We will now calculate the relationship between the initial volume and the final volume for each option. (a) For CO: When 2 moles of CO react with 1 mole of O2, they produce 2 moles of CO2. So the initial volume is V1 (CO) + V2 (O2) and the final volume is 2 * V1 (since 2 moles of CO2 are produced for each mole of CO reacted). The final volume, as given in the problem, is (V1 + V2). To satisfy this condition, we find that V1 = V2. (b) For the CO+CO2 mixture: When 2 moles of CO react with 1 mole of O2, they produce 2 moles of CO2. CO2 does not react with O2, so it does not contribute to the volume change. In this case, the final volume should be less than (V1 + V2) since some CO2 does not participate in the reaction. This option does not satisfy the problem conditions. (c) For C12O9: The reaction produces 24 moles of CO2 from a combination of 4 moles of C12O9 and 15 moles of O2. The relationship between initial and final volumes is not satisfied in this option, as it does not match V1 + V2. (d) For C3O2: The reaction produces 6 moles of CO2 from a combination of 2 moles of C3O2 and 3 moles of O2. Here, the initial volume is V1 (C3O2) + V2 (O2), and the final volume is 6 * V1/2 (since 6 moles of CO2 are produced for every 2 moles of C3O2 reacted). This leads to the final volume being 3 * V1, which does not satisfy the problem conditions.
03

Identify the correct option

According to the analysis in steps 1 and 2, option (a) is the correct answer. The unknown gas A must be CO as it is the only option that satisfies the relationship between initial and final volumes given in the problem statement.

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Most popular questions from this chapter

When \(500 \mathrm{ml} \mathrm{CO}_{2}\) gas is passed through red hot charcoal, the volume becomes \(700 \mathrm{ml}\). The volume of \(\mathrm{CO}_{2}\) converted into \(\mathrm{CO}\) is (a) \(200 \mathrm{ml}\) (b) \(300 \mathrm{ml}\) (c) \(350 \mathrm{ml}\) (d) \(500 \mathrm{ml}\)

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