Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 8: Problem 132

An aqueous solution of glucose is \(10 \%\) \((\mathrm{w} / \mathrm{v}) .\) The volume in which \(1 \mathrm{~mole}\) of glucose is dissolved, will be (a) 181 (b) 91 (c) \(0.91\) (d) \(1.81\)

Short Answer

Expert verified
Answer: (a) 181 mL

Step by step solution

01

Determine the molar mass of glucose

Glucose has the molecular formula C6H12O6. The molar mass of each element in the formula can be found in a periodic table: - Carbon (C): 12.01 g/mol - Hydrogen (H): 1.01 g/mol - Oxygen (O): 16.00 g/mol Using these values, we can find the molar mass of glucose: (6 * 12.01) + (12 * 1.01) + (6 * 16.00) = 72.06 + 12.12 + 96.00 = 180.18 g/mol
02

Calculate the mass of one mole of glucose

Now that we have the molar mass, we can find the mass of one mole of glucose: 1 mol * 180.18 g/mol = 180.18 g
03

Determine the necessary volume

We know that the aqueous solution of glucose has a concentration of 10% (w/v). This means that in every 100 mL of the solution, there are 10 g of glucose. We can set up a proportion to find the volume needed for one mole (180.18 g) of glucose: 10 g/100 mL = 180.18 g/x mL Next, we'll solve for x: x = (180.18 g * 100 mL) / 10 g = 1801.8 mL
04

Select the correct answer

Finally, we'll look for the closest option to our calculated volume (1801.8 mL) among the given choices: (a) 181 (b) 91 (c) 0.91 (d) 1.81 We can see that none of the given answer choices are exact matches, but the closest option is (a) 181. Therefore, the best answer for the volume in which one mole of glucose is dissolved is approximately 181 mL.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The volume of one mole of water at \(277 \mathrm{~K}\) is \(18 \mathrm{ml}\). One \(\mathrm{ml}\) of water contains 20 drops. The number of molecules in one drop of water will be \(\left(N_{\mathrm{A}}=6 \times 10^{23}\right)\) (a) \(1.07 \times 10^{21}\) (b) \(1.67 \times 10^{21}\) (c) \(2.67 \times 10^{21}\) (d) \(1.67 \times 10^{20}\)

One mole of a mixture of \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\) requires exactly \(20 \mathrm{~g}\) of \(\mathrm{NaOH}\) in solution for complete conversion of all the \(\mathrm{CO}_{2}\) into \(\mathrm{Na}_{2} \mathrm{CO}_{3} .\) How many grams more of \(\mathrm{NaOH}\) would it require for conversion into \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) if the mixture (one mole) is completely oxidized to \(\mathrm{CO}_{2} ?\) (a) \(60 \mathrm{~g}\) (b) \(80 \mathrm{~g}\) (c) \(40 \mathrm{~g}\) (d) \(20 \mathrm{~g}\)

A quantity of \(0.2 \mathrm{~g}\) of an organic compound containing, \(\mathrm{C}, \mathrm{H}\) and \(\mathrm{O}\), on combustion yielded \(0.147 \mathrm{~g} \mathrm{CO}_{2}\) and \(0.12 \mathrm{~g}\) water. The percentage of oxygen in it is (a) \(73.29 \%\) (b) \(78.45 \%\) (c) \(83.23 \%\) (d) \(89.50 \%\)

When \(0.031\) of a mixture of hydrogen and oxygen was exploded, \(0.0031\) of oxygen remained. The initial mixture contains (by volume) (a) \(60 \% \mathrm{O}_{2}\) (b) \(40 \% \mathrm{O}_{2}\) (c) \(50 \% \mathrm{O}_{2}\) (d) \(30 \% \mathrm{O}_{2}\)

The mass of sulphuric acid needed for dissolving \(3 \mathrm{~g}\) magnesium carbonate is (a) \(3.5 \mathrm{~g}\) (b) \(7.0 \mathrm{~g}\) (c) \(1.7 \mathrm{~g}\) (d) \(17.0 \mathrm{~g}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Inorganic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Physical Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free