Mole fraction of solute in an aqueous solution of \(\mathrm{NaOH}\) is \(0.1 .\) If the specific gravity of the solution is \(1.4\), the molarity of the solution is (a) \(6.93\) (b) \(0.1\) (c) \(71.4\) (d) \(0.14\)

Short Answer

Expert verified
Given the mole fraction of sodium hydroxide (NaOH) as 0.1, the specific gravity of the solution as 1.4, and using a 1 L volume of the solution, calculate the molarity of the NaOH solution. (Note: The calculated molarity does not match any of the provided options.)

Step by step solution

01

Calculate the mass of solute and solvent

We are given the mole fraction (\(x\)) of NaOH in the solution, which is 0.1. The mole fraction of water (\(x_{H_2O}\)) will be 1 - 0.1 = 0.9. We'll use the specific gravity of the solution (1.4) and assume a volume of 1 L (1000 mL) to find the mass of the solution: Specific gravity = Mass / Volume Mass = Specific gravity × Volume Mass = 1.4 × 1000 = 1400 g Now, we'll find the mass of sodium hydroxide (NaOH) and water (H₂O) in the solution: Mass (NaOH) = 0.1 × Mass Mass (NaOH) = 0.1 × 1400 = 140 g Mass (H₂O) = 0.9 × Mass Mass (H₂O) = 0.9 × 1400 = 1260 g
02

Calculate the number of moles of solute

To convert the mass of sodium hydroxide (NaOH) to moles, we need its molar mass, which we can calculate from the periodic table: Molar mass (NaOH) = (22.99 g/mol for Na) + (15.999 g/mol for O) + (1.0079 g/mol for H) = 39.9969 g/mol Then, we find the number of moles of NaOH: Moles (NaOH) = Mass (NaOH) / Molar mass (NaOH) Moles (NaOH) = 140 g / 39.9969 g/mol = 3.50033 mol
03

Calculate the molarity of the solution

Finally, we'll calculate the molarity of the solution by dividing the number of moles of sodium hydroxide (NaOH) by the volume of the solution (in liters): Molarity = Moles (NaOH) / Volume (L) Molarity = 3.50033 mol / 1 L = 3.50033 M Now let's compare our result to the given options: (a) 6.93 (b) 0.1 (c) 71.4 (d) 0.14 Since our calculated molarity is 3.50033 M, none of the given options match our result. We recommend reviewing the problem and checking if the given values are correct, or looking for any further hints or requirements in the exercise.

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