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Chapter 8: Problem 150

Which of the following percentage strength is not possible for a sample of oleum? (a) \(104 \%\) (b) \(109 \%\) (c) \(118 \%\) (d) \(127 \%\)

Short Answer

Expert verified
a) 104% b) 109% c) 118% d) 127% Answer: All of the given options are possible for a sample of oleum, as they all have percentage strengths greater than 100%.

Step by step solution

01

Understanding the percentage strength of Oleum

In an oleum sample, it is given as H2SO4.xSO3, which means that the mixture has x g of SO3 mixed with x g of H2SO4. The percentage strength of oleum is calculated based on the percentage of H2SO4 that would be formed if all the sulfur trioxide (SO3) present in the mixture would combine with water. Since SO3 reacts with water to form H2SO4, when it combines with water, it would form oleum with a 100% H2SO4. Hence, any percentage strength of the oleum sample must always be greater than 100%. Now let's analyze the given options using this concept.
02

Option (a): 104%

The percentage strength of oleum is 104%. Since it is greater than 100%, this means that the oleum sample contains sufficient sulfur trioxide (SO3) to form a 104% H2SO4. So, this option is possible.
03

Option (b): 109%

The percentage strength of oleum is 109%. Since it is greater than 100%, this means that the oleum sample contains sufficient sulfur trioxide (SO3) to form a 109% H2SO4. So, this option is also possible.
04

Option (c): 118%

The percentage strength of oleum is 118%. Since it is greater than 100%, this means that the oleum sample contains sufficient sulfur trioxide (SO3) to form a 118% H2SO4. So, this option is also possible.
05

Option (d): 127%

For this option, the percentage strength of oleum is 127%, which is greater than 100%. This means that the sample of oleum contains a sufficient amount of sulfur trioxide (SO3) to form a 127% H2SO4. Therefore, this option is also possible. Based on the analysis, all the given options (a), (b), (c), and (d) have percentage strengths greater than 100%. Therefore, none of the given options is impossible for a sample of oleum.

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Most popular questions from this chapter

When \(12 \mathrm{~g}\) graphite is burnt in sufficient oxygen, \(\mathrm{CO}\) as well as \(\mathrm{CO}_{2}\) is formed. If the product contains \(40 \%\) CO and \(60 \%\) \(\mathrm{CO}_{2}\) by mass and none of the reactant is left, what is the mass of oxygen gas used in combustion? (a) \(24.0 \mathrm{~g}\) (b) \(21.33 \mathrm{~g}\) (c) \(23.8 \mathrm{~g}\) (d) \(15.6 \mathrm{~g}\)

A volume of \(200 \mathrm{ml}\) of oxygen is added to \(100 \mathrm{ml}\) of a mixture containing \(\mathrm{CS}_{2}\) vapour and \(\mathrm{CO}\), and the total mixture is burnt. After combustion, the volume of the entire mixture is \(245 \mathrm{ml}\). Calculate the volume of the oxygen that remains (a) \(67.5 \mathrm{ml}\) (b) \(125.0 \mathrm{ml}\) (c) \(200.0 \mathrm{ml}\) (d) \(100.0 \mathrm{ml}\)

Equal masses of oxygen, hydrogen and methane are taken in identical conditions. What is the ratio of the volumes of the gases under identical conditions? (a) \(16: 1: 8\) (b) \(1: 16: 2\) (c) \(1: 16: 8\) (d) \(2: 16: 1\)

A compound having the empirical formula, \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\), has a molecular weight of \(170 \pm 5 .\) The molecular formula of the compound is (a) \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{2}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{3}\) (d) \(\mathrm{C}_{9} \mathrm{H}_{12} \mathrm{O}_{3}\)

A gaseous oxide contains \(30.4 \%\) of nitrogen, one molecule of which contains one nitrogen atom. The density of the oxide relative to oxygen, under identical conditions, is about (a) \(0.69\) (b) \(1.44\) (c) \(0.35\) (d) \(2.88\)
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