Chapter 8: Problem 27
Vapour density of a volatile substance is \(1.2\left(\mathrm{C}_{2} \mathrm{H}_{6}=1\right) .\) Its molecular mass would be (a) \(1.2\) (b) \(2.4\) (c) 36 (d) 72
Chapter 8: Problem 27
Vapour density of a volatile substance is \(1.2\left(\mathrm{C}_{2} \mathrm{H}_{6}=1\right) .\) Its molecular mass would be (a) \(1.2\) (b) \(2.4\) (c) 36 (d) 72
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Get started for freeA quantity of \(0.25 \mathrm{~g}\) of a substance when vaporized displaced \(50 \mathrm{~cm}^{3}\) of air at \(0^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm} .\) The gram molecular mass of the substance will be (a) \(50 \mathrm{~g}\) (b) \(100 \mathrm{~g}\) (c) \(112 \mathrm{~g}\) (d) \(127.5 \mathrm{~g}\)
Air contains \(20 \% \mathrm{O}_{2}\), by volume. What volume of air is needed at \(0^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) for complete combustion of \(80 \mathrm{~g}\) methane? (a) 101 (b) 501 (c) 2241 (d) 11201
An aqueous solution has urea and glucose in mass ratio \(3: 1\). If the mass ratio of water and glucose in the solution is \(10: 1\), then the mole fraction of glucose in the solution is (a) \(\frac{1}{110}\) (b) \(\frac{9}{110}\) (c) \(\frac{3}{110}\) (d) \(\frac{100}{110}\)
A mixture of \(254 \mathrm{~g}\) of iodine and \(142 \mathrm{~g}\) of chlorine is made to react completely to give a mixture of \(\mathrm{ICl}\) and \(\mathrm{ICl}_{3} .\) How many moles of each product are formed? \((\mathrm{I}=127, \mathrm{Cl}=35.5)\) (a) \(0.1 \mathrm{~mol}\) of \(\mathrm{ICl}\) and \(0.1 \mathrm{~mol}\) of \(\mathrm{ICl}_{3}\) (b) \(1.0 \mathrm{~mol}\) of \(\mathrm{ICl}\) and \(1.0 \mathrm{~mol}\) of \(\mathrm{ICl}_{3}\) (c) \(0.5 \mathrm{~mol}\) of \(\mathrm{ICl}\) and \(0.1 \mathrm{~mol}\) of \(\mathrm{ICl}_{3}\) (d) \(0.5 \mathrm{~mol}\) of \(\mathrm{ICl}\) and \(1.0 \mathrm{~mol}\) of \(\mathrm{ICl}_{3}\)
The empirical formula of an organic gaseous compound containing carbon and hydrogen is \(\mathrm{CH}_{2}\). The volume occupied by certain mass of this gas is exactly half of the volume occupied by the same mass of nitrogen gas under identical conditions. The molecular formula of the organic gas is (a) \(\mathrm{C}_{2} \mathrm{H}_{4}\) (b) \(\mathrm{CH}_{2}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{12}\) (d) \(\mathrm{C}_{4} \mathrm{H}_{8}\)
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