Vapour density of a volatile substance is \(1.2\left(\mathrm{C}_{2} \mathrm{H}_{6}=1\right) .\) Its molecular mass would be (a) \(1.2\) (b) \(2.4\) (c) 36 (d) 72

Short Answer

Expert verified
Answer: The molecular mass of the volatile substance is 36.

Step by step solution

01

Identify the Reference Molecular Mass

Ethane, C2H6, is given to have a vapor density of 1. This means that its vapor density is the same as its molecular mass. The molecular mass of Ethane can be calculated by adding the atomic masses of its component atoms: 2 Carbon atoms (2 x 12) and 6 Hydrogen atoms (6 x 1). Therefore, the molecular mass of Ethane is 30.
02

Calculate the Molecular Mass using the Relative Vapor Density

The volatile substance's vapor density is given to be 1.2 times that of Ethane. To find its molecular mass, we simply need to multiply the molecular mass of Ethane by this factor: Molecular mass of volatile substance = Molecular mass of Ethane x Relative vapor density Molecular mass of volatile substance = 30 x 1.2
03

Solve for the Molecular Mass

After multiplying the molecular mass of Ethane by the relative vapor density, we can find the molecular mass of the volatile substance: Molecular mass of volatile substance = 30 x 1.2 = 36 The molecular mass of the volatile substance is 36. Therefore, the correct answer is (c) 36.

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