\(\mathrm{X}+\mathrm{CuSO}_{4} \rightarrow \mathrm{XSO}_{4}+\mathrm{Cu}\) \(\mathrm{Y}+\mathrm{CuSO}_{4} \rightarrow \mathrm{YSO}_{4}+\mathrm{Cu}\), in these reactions \(\mathrm{X}\) and \(\mathrm{Y}\) may be (a) \(\mathrm{Zn}, \mathrm{Ag}\) (b) \(\mathrm{Zn}, \mathrm{Fe}\) (c) Fe, \(\mathrm{Ag}\) (d) \(\mathrm{Ag}, \mathrm{Al}\)

Short Answer

Expert verified
Answer: (b) Zn, Fe can replace Cu in the replacement reactions involving CuSO4, as both are more reactive than Cu.

Step by step solution

01

Review the reactivity series

We have to recall the reactivity series from most reactive to least reactive to know which elements will react with CuSO4. The common non-reaction elements are (from least reactive): Au, Pt, Ag, Cu, Hg, Pb, Bi, Sn, H, As, Sb, Cu, Ni, Co, Fe, Cd, Pt, Al, Mn, Cr, Zn, Mg, Ca, Sr, Ba, Ra, Rb, Cs, K, Na, Li.
02

Determine the reactivity of given elements

We will determine the reactivity order of the given options. (a) Zn, Ag - Zn is more reactive than Cu, while Ag is less reactive than Cu. (b) Zn, Fe - Zn and Fe both are more reactive than Cu. (c) Fe, Ag - Fe is more reactive than Cu, while Ag is less reactive than Cu. (d) Ag, Al - Ag is less reactive than Cu, while Al is more reactive than Cu.
03

Choose the correct option

We are looking for the option where both X and Y are more reactive than Cu and will therefore react with CuSO4. From step 2, we can see that option (b) has both elements, Zn and Fe, more reactive than Cu. Therefore, X and Y can be Zn and Fe in these reactions. The correct answer is (b) Zn, Fe.

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