For \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\), which is the correct mole relationship? (a) \(9 \times\) mole of \(\mathrm{Cu}=\) mole of \(\mathrm{O}\) (b) \(5 \times\) mole of \(\mathrm{Cu}=\) mole of \(\mathrm{O}\) (c) \(9 \times\) mole of \(\mathrm{Cu}=\) mole of \(\mathrm{O}_{2}\) (d) mole of \(\mathrm{Cu}=5 \times\) mole of \(\mathrm{O}\)

Short Answer

Expert verified
Answer: (a) 9 × mole of Cu = mole of O

Step by step solution

01

Determine the number of Cu and O atoms in the compound

CuSO4·5H2O is Copper(II) sulfate pentahydrate. It consists of one Cu atom, one sulfate ion (SO4) and five water molecules (H2O). Therefore, let's break the compound into its constituents: - Cu: 1 - SO4: 1 (which contains 1 sulfur atom and 4 oxygen atoms) - 5H2O: 5 water molecules (each containing 2 hydrogen atoms and 1 oxygen atom).
02

Count the number of Cu and O atoms

Now, let's count the number of Cu and O atoms in the compound: - Cu atoms: 1 - O atoms: 4 (from SO4) + 5 (from 5H2O) = 9
03

Compare the given options with the calculated number of moles

Given the number of Cu and O atoms, let's consider each of the given options: (a) \(9 \times \text{ mole of Cu} = \text{mole of O}\) – This option matches with our calculation, as there is 1 mole of Cu and 9 moles of O in the compound. (b) \(5 \times \text{mole of Cu} = \text{ mole of O}\) – This option is incorrect. (c) \(9 \times \text{ mole of Cu} = \text{ mole of } O_{2}\) – This option is incorrect, as we are considering the mole relationship between Cu and O atoms, not O2 molecules. (d) mole of Cu\( = 5 \times\) mole of O – This option is also incorrect.
04

Identify the correct mole relationship

Based on our analysis, the correct mole relationship for the compound CuSO4·5H2O is: (a) \(9 \times \text{ mole of Cu} = \text{ mole of O}\)

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