A reaction whose heat of reaction shows the bond energy of \(\mathrm{HCl}\) is (a) \(\mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{H}(\mathrm{g})+\mathrm{Cl}(\mathrm{g})\) (b) \(2 \mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{Hl}(\mathrm{g})+\mathrm{Cll}(\mathrm{g})\) (c) \(\mathrm{HCl}(\mathrm{g}) \longrightarrow \frac{1}{2} \mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g})\) (d) \(\mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{H}^{+}(\mathrm{g}) \longrightarrow \mathrm{Cl}^{-}(\mathrm{g})\)

Short Answer

Expert verified
The correct reaction which shows the bond energy of HCl is (a).

Step by step solution

01

Understanding the concept

Bond energy refers to the amount of energy required to break a bond between two covalently bonded atoms. In this case, we want an equation that shows breaking the bond in HCl.
02

Analyzing the reactions

We examine each of the given reactions individually:(a) \( \mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{H}(\mathrm{g})+\mathrm{Cl}(\mathrm{g}) \) - In this reaction, the bond between hydrogen and chlorine is broken to form gaseous hydrogen and chlorine. This reaction shows breaking the bond in HCl.(b) \( 2 \mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{Hl}(\mathrm{g})+\mathrm{Cll}(\mathrm{g}) \) - This reaction does not make chemical sense. Since there are no elements named Hl and Cll, we can disregard this option.(c) \( \mathrm{HCl}(\mathrm{g}) \longrightarrow \frac{1}{2} \mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g}) \) - In this reaction, HCl is broken down into half a molecule each of hydrogen and chlorine gas. Physically, there is no such thing as half a molecule, so this reaction is not feasible.(d) \( \mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{H}^{+}(\mathrm{g})\longrightarrow \mathrm{Cl}^{-}(\mathrm{g}) \) - This reaction seems to break HCl into a hydrogen and a chloride ion. However, ions do not exist freely in gaseous state. So this option is incorrect.
03

Selecting the correct reaction

Based on the analysis, the first reaction is the correct answer. This reaction represents the breaking of the bond in HCl, which gives the bond energy of HCl. The rest of the reactions are either chemically incorrect or physically impossible.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free