Chapter 13: Problem 11
In which of the following cases does the reaction go farthest to completion? (a) \(K=10\) (b) \(K=1\) (c) \(K=10^{3}\) (d) \(K=10^{-2}\)
Chapter 13: Problem 11
In which of the following cases does the reaction go farthest to completion? (a) \(K=10\) (b) \(K=1\) (c) \(K=10^{3}\) (d) \(K=10^{-2}\)
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Get started for freeThe rate of forward reaction is two times that of the backward reaction at a given temperature and identical concentration, \(K_{\text {equilimbrium }}\) is, (a) \(1.5\) (b) \(0.5\) (c) \(2.5\) (d) \(2.0\)
With increase in temperature, equilibrium constant of a reaction
(a) always decreases
(b) always increases
(c) may increase or decrease depending upon whether \(n_{p}
What will be the equilibrium constant at \(717 \mathrm{~K}\) for the reaction $$ 2 \mathrm{HI}(\mathrm{g}) \rightleftharpoons \frac{1}{2} \mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{I}_{2}(\mathrm{~g}) $$ if its value for the reaction $$ \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g}) \text { at } 717 \mathrm{~K} \text { is } 64 ? $$ (a) 8 (b) 64 (c) \(\frac{1}{64}\) (d) \(\frac{1}{8}\)
In a reaction \(\mathrm{PCl}_{5}(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\), the equilibrium concentrations of \(\mathrm{PC}_{5}\) and \(\mathrm{PCl}_{3}\) are \(0.4\) and \(0.2\) moles/litre respectively. If the value of \(K_{c}\) is \(0.5\), what is the concentration of \(\mathrm{C} 1_{2}\) in mole/litre? (a) \(1.0\) (b) \(1.5\) (c) \(0.5\) (d) \(2.0\)
In which of the following reaction is \(K_{p}\) less than \(K_{c} ?\) (a) \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})\) (b) \(\mathrm{PCl}_{5}(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\) (c) \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})\) (d) \(2 \mathrm{SO}_{3}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})\)
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