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Chapter 17: Problem 3

In spite of various acid and base-producing reactions in our body, the pH of our blood is (a) \(5.4\) (b) \(6.4\) (c) \(7.4\) (d) \(8.4\)

Short Answer

Expert verified
The correct option is (c) 7.4.

Step by step solution

01

Understanding pH scale

The pH scale measures how acidic or basic a substance is. It ranges from 0-14. A pH of 7 is neutral. A pH less than 7 is acidic and a pH greater than 7 is basic.
02

Identifying human blood pH

In the human body, the pH of blood has to be maintained in a very narrow range to function normally and is tightly regulated between 7.35 and 7.45, slightly basic.
03

Choose correct option

From the options given (5.4, 6.4, 7.4, 8.4), the closest to this range is 7.4.

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Most popular questions from this chapter

An example of an acid buffer is a solution of (a) ammonium acetate (b) a mixture of \(\mathrm{NH}_{4} \mathrm{OH}+\mathrm{NH}_{4} \mathrm{Cl}\) (c) a mixture of \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{CH}_{3} \mathrm{COONa}\) (d) a solution of \(\mathrm{CH}_{3} \mathrm{COONa}\)

Heat of neutralisation of a strong acid and weak base is less than \(57.3 \mathrm{~kJ} \mathrm{~mol}^{-1}\). This is because (a) all the acid is not ionised (b) all the base is not ionised (c) the ionisation is complete but further reaction does not take place (d) some of the heat is transferred to the surroundings

An example of a basic buffer is a solution of (a) \(\mathrm{NH}_{4} \mathrm{OH}+\mathrm{NH}_{4} \mathrm{Cl}\) (b) \(\mathrm{NH}_{4} \mathrm{OH}+\mathrm{HCl}\) (c) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) (d) \(\mathrm{NH}_{4} \mathrm{OH}+\mathrm{NaOH}\)

Both anionic and cationic hydrolysis occur in the case of (a) salts of strong acid and strong base (b) salts of strong acid and weak base (c) salts of weak acid and strong base (d) salts of weak acid and weak base

The \(\mathrm{pH}\) of a solution of salt of strong acid and weak base is given by a) \(\frac{1}{2}\left(\log K_{w^{\prime}}+\log K_{b}+\log C\right)\) (b) \(\frac{1}{2}\left(\log K_{w}-\log K_{b}-\log C\right)\) c) \(\frac{1}{2}\left(\log K_{w^{\prime}}-\log K_{b}+\log C\right)\) d) \(\frac{1}{2}\left(-\log K_{w^{\prime}}-\log K_{b}-\log C\right)\)
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